[Devel] [PATCH 0/2] NFSD: fix races in service per-net resources allocation

Stanislav Kinsbursky skinsbursky at parallels.com
Mon Feb 11 22:49:12 PST 2013


11.02.2013 20:37, J. Bruce Fields пишет:
> On Mon, Feb 11, 2013 at 10:18:18AM +0400, Stanislav Kinsbursky wrote:
>> This one looks a bit complicated and confusing to me. Probably because
>> I'm not that familiar with service transports processing logic.  So,
>> as I can see, we now try to run over all per-net pool-assigned
>> transports, remove them from "ready" queue and delete one by one.
>> Then we try to enqueue all temporary sockets. But where in enqueueing
>> of permanent sockets? I.e. how does they be destroyed with this patch?
>> Then we once again try to run over all per-net pool-assigned
>> transports, remove them from "ready" queue and delete one by one.  Why
>> twice? I.e. why not just lose them, then enqueue them and
>> svc_clean_up_xprts()?
>
> I think you missed the first svc_close_list?:
>

Yeah, thanks! To many deleted lines confused me.

>>>   	svc_close_list(serv, &serv->sv_permsocks, net);
>>> +	svc_clean_up_xprts(serv, net);
>>> +	svc_close_list(serv, &serv->sv_tempsocks, net);
>>> +	svc_clean_up_xprts(serv, net);
>
> The idea is that before we'd like to close all the listeners first, so
> that they aren't busy creating more tempsocks while we're trying to
> close them.
>
> I overlooked a race, though: if another thread was already handling an
> accept for one of the listeners then it might not get closed by that
> first svc_clean_up_xprts.
>
> I guess we could do something like:
>
> 	delay = 0;
>
>      again:
> 	numclosed = svc_close_list(serv, &serv->sv_permsocks, net);
> 	numclosed += svc_close_list(serv, &serv->sv_tempsocks, net);
> 	if (numclosed) {
> 		svc_clean_up_xprts(serv, net);
> 		msleep(delay++);
> 		goto again;
> 	}
>
> Seems a little cheesy, but if we don't care much about shutdown
> performance in a rare corner case, maybe it's the simplest way out?
>

Agreed. This part (per-net shutdown) has enough logical complexity already and would be great to not
increase it.


-- 
Best regards,
Stanislav Kinsbursky



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