[Devel] Re: 2.6.33-rc4 i686 clone function looping (seems real!)

Serge E. Hallyn serue at us.ibm.com
Tue Jan 19 14:15:35 PST 2010


Quoting Jean-Marc Pigeon (jmp at safe.ca):
> Hello Serge,
> 
> 	Thanks for the small test, I do confirm
> 	there is the same problem here with it, 
> 	as soon started the program use ALL available 
> 	CPU cycle (minus some few %) and NEVER
> 	EVER come back from "clone" function.
> 	The ONLY way I found to recover the
> 	system is to power it down (sic!).
> 
> 	See attachment, your program, the 
> 	.config file, and cpu information
> 	(I put back your test too, (done 
> 	 cosmetic changes only)).
> 
> 	Once again, clone call on 2.6.32.3
> 	is working fine.
> 
> 	Sorry to bother the list, I was "expecting"
> 	a Stack size problem, but I increase
> 	your value from 4 to 10, with the same result.
> 	Hopefully it could be something I overlooked
> 	with my Kernel config file, if someone
> 	want to have a look I attached it.
> 
> 	My guess for now it is something within
> 	the clone code specific to i386.
> 	
> 	I 'll try to pin point within the 
> 	clone code.
> 
> 	(could someone check tstclone.c under 
> 	 i386 arch and confirm trouble?)

Also might echo 1 > /proc/sys/kernel/sysrq before running the test, then
hit alt-sysrq-d to show all locks being held, alt-sysrq-l to show
stacks, alt-sysrq-p to dump registers, and alt-sysrq-t to dump tasks.

-serge
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