[Devel] Re: 2.6.33-rc4 i686 clone function looping (seems real!)
Serge E. Hallyn
serue at us.ibm.com
Tue Jan 19 14:15:35 PST 2010
Quoting Jean-Marc Pigeon (jmp at safe.ca):
> Hello Serge,
>
> Thanks for the small test, I do confirm
> there is the same problem here with it,
> as soon started the program use ALL available
> CPU cycle (minus some few %) and NEVER
> EVER come back from "clone" function.
> The ONLY way I found to recover the
> system is to power it down (sic!).
>
> See attachment, your program, the
> .config file, and cpu information
> (I put back your test too, (done
> cosmetic changes only)).
>
> Once again, clone call on 2.6.32.3
> is working fine.
>
> Sorry to bother the list, I was "expecting"
> a Stack size problem, but I increase
> your value from 4 to 10, with the same result.
> Hopefully it could be something I overlooked
> with my Kernel config file, if someone
> want to have a look I attached it.
>
> My guess for now it is something within
> the clone code specific to i386.
>
> I 'll try to pin point within the
> clone code.
>
> (could someone check tstclone.c under
> i386 arch and confirm trouble?)
Also might echo 1 > /proc/sys/kernel/sysrq before running the test, then
hit alt-sysrq-d to show all locks being held, alt-sysrq-l to show
stacks, alt-sysrq-p to dump registers, and alt-sysrq-t to dump tasks.
-serge
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