[Devel] Re: [PATCH 2/3] ftrace: use struct pid
Dipankar Sarma
dipankar at in.ibm.com
Thu Dec 4 19:17:36 PST 2008
On Thu, Dec 04, 2008 at 05:07:02AM -0800, Dave Hansen wrote:
> On Thu, 2008-12-04 at 04:56 -0800, Dave Hansen wrote:
> > On Thu, 2008-12-04 at 04:42 -0800, Eric W. Biederman wrote:
> > >
> > > > +static void clear_ftrace_pid_task(struct pid **pid)
> > > > +{
> > > > + struct task_struct *p;
> > > > +
> > > rcu_read_lock();
> > >
> > > > + do_each_pid_task(*pid, PIDTYPE_PID, p) {
> > > > + clear_tsk_trace_trace(p);
> > > > + } while_each_pid_task(*pid, PIDTYPE_PID, p);
> > > rcu_read_unlock()
> > >
> > > > + put_pid(*pid);
> > > > +
> > > > + *pid = NULL;
> > > > +}
> >
> > Could we get away with sticking the rcu_read_{un}lock() inside those
> > macros? Those are going to get used in pretty high level code and we're
> > allowed to nest rcu_read_lock(). No danger of deadlocks or lock
> > inversions.
>
> Why don't any of the other users of do_each_pid_task() use
> rcu_read_lock()? They all seem to be under read_lock(&tasklist_lock)
> (except one is under a write lock of the same).
The pid hash list is protected by tasklist_lock, right ? If so,
holding read_lock(&tasklist_lock) will make this safe, you don't
need rcu_read_lock/unlock(). This isn't a lock-free reader.
Thanks
Dipankar
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