[Devel] Re: [RFC][PATCH] Make access to taks's nsproxy liter
Pavel Emelyanov
xemul at openvz.org
Thu Aug 9 00:15:49 PDT 2007
Paul E. McKenney wrote:
> On Wed, Aug 08, 2007 at 08:41:07PM +0400, Oleg Nesterov wrote:
>> This time Paul E. McKenney actually cc'ed, sorry for the extra
>> noise...
>>
>> On 08/08, Pavel Emelyanov wrote:
>>> When someone wants to deal with some other taks's namespaces
>>> it has to lock the task and then to get the desired namespace
>>> if the one exists. This is slow on read-only paths and may be
>>> impossible in some cases.
>>>
>>> E.g. Oleg recently noticed a race between unshare() and the
>>> (just sent for review) pid namespaces - when the task notifies
>>> the parent it has to know the parent's namespace, but taking
>>> the task_lock() is impossible there - the code is under write
>>> locked tasklist lock.
>>>
>>> On the other hand switching the namespace on task (daemonize)
>>> and releasing the namespace (after the last task exit) is rather
>>> rare operation and we can sacrifice its speed to solve the
>>> issues above.
>> Still it is a bit sad we slow down process's exit. Perhaps I missed
>> some other ->nsproxy access, but can't we make a simpler patch?
>>
>> --- kernel/fork.c 2007-07-28 16:58:17.000000000 +0400
>> +++ /proc/self/fd/0 2007-08-08 20:30:33.325216944 +0400
>> @@ -1633,7 +1633,9 @@ asmlinkage long sys_unshare(unsigned lon
>>
>> if (new_nsproxy) {
>> old_nsproxy = current->nsproxy;
>> + read_lock(&tasklist_lock);
>> current->nsproxy = new_nsproxy;
>> + read_unlock(&tasklist_lock);
>> new_nsproxy = old_nsproxy;
>> }
>>
>>
>> This way ->nsproxy is stable under task_lock() or write_lock(tasklist).
>>
>>> +void switch_task_namespaces(struct task_struct *p, struct nsproxy *new)
>>> +{
>>> + struct nsproxy *ns;
>>> +
>>> + might_sleep();
>>> +
>>> + ns = p->nsproxy;
>>> + if (ns == new)
>>> + return;
>>> +
>>> + if (new)
>>> + get_nsproxy(new);
>>> + rcu_assign_pointer(p->nsproxy, new);
>>> +
>>> + if (ns && atomic_dec_and_test(&ns->count)) {
>>> + /*
>>> + * wait for others to get what they want from this
>>> + * nsproxy. cannot release this nsproxy via the
>>> + * call_rcu() since put_mnt_ns will want to sleep
>>> + */
>>> + synchronize_rcu();
>>> + free_nsproxy(ns);
>>> + }
>>> +}
>> (I may be wrong, Paul cc'ed)
>>
>> This is correct with the current implementation of RCU, but strictly speaking,
>> we can't use synchronize_rcu() here, because write_lock_irq() doesn't imply
>> rcu_read_lock() in theory.
>
> Can you use synchronize_sched() instead? The synchronize_sched()
#define synchronize_sched() synchronize_rcu()
they are the same? what's the point?
> primitive will wait until all preempt/irq-disable code sequences complete.
> Therefore, it would wait for all write_lock_irq() code sequences to
> complete.
But we don't need this. Iff we get the nsproxy under rcu_read_lock() all
we need is to wait for RCU sections to complete.
> Does this work?
>
> Thanx, Paul
>
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