[CRIU] [RFC PATCH 18/21] zdtm: use the multi-test launcher by default

[Andrew Vagin]

What does this mean? All test will be executed via launcher by default?
Can we wait a bit while it's stabialized? I'm going to create a new job
in ci.openvz.org and when it will be stable enought, we can make it as a
default one.

On Fri, Feb 19, 2016 at 05:50:41PM +0300, Ivan Shapovalov wrote:
> Signed-off-by: Ivan Shapovalov <intelfx at intelfx.name>
> ---
>  test/zdtm.py                 | 2 +-
>  test/zdtm/live/Makefile.live | 2 +-
>  2 files changed, 2 insertions(+), 2 deletions(-)
> 
> diff --git a/test/zdtm.py b/test/zdtm.py
> index b1a58aa..3671761 100755
> --- a/test/zdtm.py
> +++ b/test/zdtm.py
> @@ -347,7 +347,7 @@ class zdtm_test:
>  		self.__pid = 0
>  		self.__flavor = flavor
>  		self.__freezer = freezer
> -		self._bins = [ name ]
> +		self._bins = [ name, os.path.normpath(os.path.dirname(name) + "/../../launcher/launcher") ]
>  		self._env = {}
>  		self._deps = desc.get('deps', [])
>  		self.auto_reap = True
> diff --git a/test/zdtm/live/Makefile.live b/test/zdtm/live/Makefile.live
> index 1dff0ec..29cfb78 100644
> --- a/test/zdtm/live/Makefile.live
> +++ b/test/zdtm/live/Makefile.live
> @@ -39,7 +39,7 @@ $(TST_DIR_FILE:%=%.args):
>  	@echo --dirname=$(basename $@).dir.test --filename=$(basename $@).test
>  
>  %.pid: %
> -	$(<D)/$(<F) $(shell $(MAKE) -s $<.args-global) $(shell $(MAKE) -s $<.args)
> +	../../launcher/launcher $(shell $(MAKE) -s $<.args-global) --lib $(<D)/$(<F) $(shell $(MAKE) -s $<.args)
>  
>  %.out: %.pid %
>  	-kill -TERM `cat $<`
> -- 
> 2.7.1
> 
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